[Tutor] To get numeric prefix in a string if present

[Manprit Singh]

 Dear Sir ,
st = "23fgh"
st[:st.index(st.lstrip("0123456789"))]
what about this ? This works well too for the said operation of getting the
numeric prefix of a string .

On Tue, May 4, 2021 at 9:33 AM Manprit Singh <manpritsinghece at gmail.com>
wrote:

> Dear sir ,
> Consider the problem of getting numeric prefix in a string if present.
>
> st = "23fgh"
> st1 = ""
> for ele in st:
>     if ele.isdigit():
>         st1 += ele
>     else:
>         break
> print(st1 or "Numeric prefix not in string" )
>
> Here st variable contains the string from which the numeric prefix has to
> be retrieved, which is 23 . The code written above gives the right answer.
>
> My major question is - The way I have used break statement  with else  is
> correct ?
> iIam using an empty string st1 and then concatenating the digit  characters
> with it, this doesn't feel pythonic. need to know any better way to solve
> this .
> Kindly guide
>
> Regards
> Manprit Singh
>
>