[Tutor] A dictionary question

[Phil]

Just a quick one while I stop for afternoon tea.

Using the example provide by Mats, if I print(pairs) I get:

Counter({(4, 6): 2, (3, 4): 1, (3, 6): 1 etc.

How would I print the pairs so they look like this:

(4,6) 2
(3,4) 1
(3,6) 1

My feeble attempt is under the example code. I have looked at a couple 
of collections tutorials but I cannot relate what I'm seeing to the 
example below.

I'm also wondering how I might do something like this:

if count == 2:

     do this

row = [{7,3},{5},{4,6,8},{7,8},{1},{9,3},{7,9},{4,6,3},{2}]
#row = [{5},{6},{3},{4,7,5},{1,2,4,5},{1,7,5},{1,2,4,7,9},{8},{1,2,4,7,9}]

set_list = [{1, 2}, {1, 3}, {1, 4}, {1, 5}, {1, 6}, {1, 7}, {1, 8}, {1, 9},
             {2, 3}, {2, 4}, {2, 5}, {2, 6}, {2, 7}, {2, 8}, {2, 9},
             {3, 4}, {3, 5}, {3, 6}, {3, 7}, {3, 8}, {3, 9},
             {4, 5}, {4, 6}, {4, 7}, {4, 8}, {4,9},
             {5, 6}, {5, 7}, {5, 8}, {5, 9},
             {6, 7}, {6, 8}, {6, 9},
             {7, 8}, {7, 9},
             {8, 9}
             ]

from collections import Counter

pairs = Counter()

for s in set_list:
     for r in row:
         if s.issubset(r):
             pairs[tuple(sorted(s))] += 1

print(pairs)

for i in range(9):
     print(pairs[i])

-- 
Regards,
Phil