[Tutor] problem solving with lists

[alan.gauld at yahoo.co.uk]

   On 18 Mar 2022 13:07, marcus.luetolf at bluewin.ch wrote:

     >lst = [['a', 'b', 'c'], ['d', 'e', 'f'], ['a', 'b', 'g'], ['b', 'c',
     'h']]

     >n = len(lst)
     >p = 0
     >new_lst = []
     >while n > 0:
     >    pair1 = lst[p][0:2]
     >    pair2 = list(lst[p][0]+ lst[p][2])
     >    pair3 = lst[p][1:]
     >    print('pair1:', pair1, 'pair2: ', pair2, 'pair3: ', pair3)
     >    if pair1 or pair2 or pair3 not in new_lst

   I suspect that's not doing what you think. Python sees it as
   If pair 1 not empty
   Or pair2 not empty
   Or pair3 not in newlist
   I don't think that's what you want. 
   BTW why does 
   For p in lst not work? 
   It seems to be what you are effectively doing... 
   Alan G 

     From my phone, apologies for any typing errors...