[Tutor] problem solving with lists

[alan.gauld at yahoo.co.uk]

   On 18 Mar 2022 15:12, marcus.luetolf at bluewin.ch wrote:

     …many thanks for your quick replay.

     When I used a for loop :

      

     >lst = [['a', 'b', 'c'], ['d', 'e', 'f'], ['a', 'b', 'g'], ['b', 'c',
     'h']]

     >sub_lst = []

     >for p in lst:

     >    pair1 = lst[p][0:2]

   P is not an index its the actual sublist. So you just need
   Pair1 = p[0:2]

     >

     > ected. But I don’t understand

     what you mean with

     If pair 1 not empty

     Or pair2 not empty

     Or pair3 not in newlist

      

     What is the difference between pair not beeing empty or not beeing in
     new_list ?

   Pair not empty means pair contains anything other than the empty list.
   Pair not in newlist means pair is not empty and it's contents are not I.
   Newlist. Very different! 

     How should I define the if condition properly ?

   You need, I assume, 
   If Pair1 not in newlist 
   Or pair2 not in newlist
   Or pair3 not in newlist
   Alan g.