[XML-SIG] speed question re DOM parsing

[Juergen Hermann]

On Fri, 23 Jun 2000 12:12:08 +0200, Juergen Hermann wrote:

>The result is obvious, and also what I expected.

Only I forgot about name lookup rules, so...

Length of testtext is 967
              adding    27.935
            stringio    24.717
           stringio2    19.703

Length of testtext is 967
              adding    27.583
            stringio    24.43
           stringio2    19.544

---%<----------------------------------
# Timings on char-wise string growing

import time, string, sys, cStringIO, array

testtext = open(sys.argv[0], "rt").read()

def timing(f, n, a):
    print "%20s" % (f.__name__,),
    r = range(n)
    t1 = time.clock()
    for i in r:
        f(a); f(a); f(a); f(a); f(a); f(a); f(a); f(a); f(a); f(a)
    t2 = time.clock()
    print "\t", round(t2-t1, 3)

def adding(x):
    result = ""
    for ch in testtext:
        result = result + ch
    #print "adding(): len =", len(result)

def stringio(x):
    chars = cStringIO.StringIO()
    for ch in testtext:
        chars.write(ch)
    result = chars.getvalue()
    #print "stringio(): len =", len()

def stringio2(x):
    chars = cStringIO.StringIO()
    push = chars.write
    for ch in testtext:
        push(ch)
    result = chars.getvalue()
    #print "stringio(): len =", len()

print "Length of testtext is", len(testtext)

n=1000
timing(adding, n, None)
timing(stringio, n, None)
timing(stringio2, n, None)