[XML-SIG] SimpleXMLRPCServer Question

Mark Bucciarelli mark@easymailings.com
Wed, 1 Jan 2003 18:15:00 -0500

I'm trying to use the pycrypto module to pass encrypted login information=
 to a=20
SimpleXMLRPCServer, but I'm getting a 500 Internal Error.  I suspect it's=
either a bug in the BaseHTTPServer or the cipertext argument contains som=
characters that aren't allowed.

I think the 500 error is triggered because the statement

    data =3D self.rfile.read(int(self.headers["content-length"]))

in the SimpleXMLRPCRequestHandler throws an exception.

I've stubbed the server login function to simply return "FAILED" no matte=
what is passed in.  When I call server.login("a"), it returns "FAILED" bu=
when I pass in cipher.encrypt("a 16 byte string") I get a 500 error.

So, is there some limit on the characters I can pass to an XMLRPC method?