[XML-SIG] node identity with libxml2
veillard at redhat.com
Thu Jan 29 06:56:22 EST 2004
On Thu, Jan 29, 2004 at 11:40:21AM +0000, Matt Patterson wrote:
> I'm using libxml2 and I'm trying to determine the intersection of two
> lists of nodes, where each list is a leaf-to-root chain of ancestors.
> The lists do have a point of intersection.
> printing the trees shows this:
> tree1: [<xmlNode (start) object at 0x6d788>, <xmlNode (alpha) object at
> tree2: [<xmlNode (end) object at 0x6d878>, <xmlNode (alpha) object at
> (I've snipped the ends of the lists for clarity.)
> Now, I know that the <xmlNode (alpha) object> in each list are
> references to the same node: There's only one <alpha> element in the
> entire document. However, if I do tree1 == tree2 it returns
> false, which is a problem.
right, the underlying C object are the same but new wrappers are build
on the fly. The equality should be defined by testing the C objects pointers,
I don't know how to do this,
Daniel Veillard | Red Hat Network https://rhn.redhat.com/
veillard at redhat.com | libxml GNOME XML XSLT toolkit http://xmlsoft.org/
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