[XML-SIG] Learning to use elementtree

[Stefan Behnel]

Hi,

Doran, Harold wrote:
> Well, I think I'm getting close. But, I think this is similar to the
> problem I had when I started. This seems to create a huge data file with
> all information under the first item, and then again all information
> under the second item and so forth.
> 
> for statentityref in \
> et.findall('admin/responseanalyses/analysis/analysisdata/statentityref')
> :   
>    print >> f, statentityref.attrib['id']
>    for statentityref in \
>  
> et.findall('admin/responseanalyses/analysis/analysisdata/statentityref/s
> tatentityref'):   
>       for statval in statentityref.findall('statval'):
>          print >> f, statentityref.attrib['id'], '\t',
> statval.attrib['type'], '\t', statval.attrib['value']

I think you should read the previous post again. You are nesting three loops
here where two would do what you want.

Stefan


>> -----Original Message-----
>> From: J. Cliff Dyer [mailto:jcd at unc.edu] 
>> Sent: Wednesday, April 02, 2008 3:36 PM
>> To: Doran, Harold
>> Cc: xml-sig at python.org
>> Subject: Re: [XML-SIG] Learning to use elementtree
>>
>> On Wed, 2008-04-02 at 15:28 -0400, Doran, Harold wrote:
>>> Indeed, navigating the xml is tough (for me). I have been 
>> able to get 
>>> the following to work. I put in "Sub Element" to indicate the new 
>>> section of data. But, from looking at the text output, one doesn't 
>>> know which item these sub elements belong to. I think the 
>> solution is 
>>> to create an index like 13965-0 to show that this is the 
>>> subinformation from the item above it. That seems to be 
>> where I am getting stuck.
>>> Although, I am open to other suggestions on how to best 
>> represent the 
>>> output.
>>>
>>> from xml.etree.ElementTree import ElementTree as ET
>>>
>>> filename = raw_input("Please enter the AM XML file: ") new_file = 
>>> raw_input("Save this file as: ")
>>>
>>> # create a new file defined by the user f = open(new_file, 'w')
>>>
>>> et = ET(file=filename)
>>>
>>> for statentityref in \
>>>
>> et.findall('admin/responseanalyses/analysis/analysisdata/statentityref
>>> ')
>>> :
>>>     for statval in statentityref.findall('statval'):
>>>       print >> f, statentityref.attrib['id'], '\t', 
>>> statval.attrib['type'], '\t', statval.attrib['value']
>>>
>>> f.write("\n\n")
>>> f.write("Sub Element\n\n")
>>>
>>> for statentityref in \
>>>
>> et.findall('admin/responseanalyses/analysis/analysisdata/statentityref
>>> /s
>>> tatentityref'):
>>>     for statval in statentityref.findall('statval'):
>>>       print >> f, statentityref.attrib['id'], '\t', 
>>> statval.attrib['type'], '\t', statval.attrib['value']
>>> f.close()
>> Do you want your second statentityref loop to be based on its 
>> parent statentityref?  If so, you need to nest it in the 
>> original loop, and use an xpath relative to your outer 
>> statentityref (and watch for name collisions).