Re: [Kwant] Units of the wavefunction and velocity
Great, thanks a lot! On Mon, Jan 23, 2017 at 10:15 AM, Anton Akhmerov < anton.akhmerov+kd@gmail.com> wrote:
Thank you. Then to calculate the velocity, should I just divide the probability current by the integral of |đ|2 over the unit cell?
You could do that, but this is already done in Kwant, and you can read the velocities off from the modes object [1].
Best, Anton
[1]: https://kwant-project.org/doc/1/reference/generated/kwant. physics.PropagatingModes#kwant.physics.PropagatingModes
Hi, You could do that, but this is already done in Kwant, and you can read the
velocities off from the modes object [1].
I was able to obtain the velocities from the modes object. I confirmed that modes.velocities is just the inverse of integral |đ|2 over the unit cell. If I did the math correctly, I got the units of modes.velocities to be eV (energy units of my Hamiltonian). How can I convert this to lets say m/s? Thanks, Harshad On Mon, Jan 23, 2017 at 10:18 AM, Harshad Sahasrabudhe <hsahasra@purdue.edu> wrote:
Great, thanks a lot!
On Mon, Jan 23, 2017 at 10:15 AM, Anton Akhmerov < anton.akhmerov+kd@gmail.com> wrote:
Thank you. Then to calculate the velocity, should I just divide the probability current by the integral of |đ|2 over the unit cell?
You could do that, but this is already done in Kwant, and you can read the velocities off from the modes object [1].
Best, Anton
[1]: https://kwant-project.org/doc/1/reference/generated/kwant.ph ysics.PropagatingModes#kwant.physics.PropagatingModes
Can I just do 1/2 m*v^2 = modes.velocities, assuming parabolic dispersion? On Mon, Jan 23, 2017 at 3:13 PM, Harshad Sahasrabudhe <hsahasra@purdue.edu> wrote:
Hi,
You could do that, but this is already done in Kwant, and you can read the
velocities off from the modes object [1].
I was able to obtain the velocities from the modes object. I confirmed that modes.velocities is just the inverse of integral |đ|2 over the unit cell. If I did the math correctly, I got the units of modes.velocities to be eV (energy units of my Hamiltonian). How can I convert this to lets say m/s?
Thanks, Harshad
On Mon, Jan 23, 2017 at 10:18 AM, Harshad Sahasrabudhe < hsahasra@purdue.edu> wrote:
Great, thanks a lot!
On Mon, Jan 23, 2017 at 10:15 AM, Anton Akhmerov < anton.akhmerov+kd@gmail.com> wrote:
Thank you. Then to calculate the velocity, should I just divide the probability current by the integral of |đ|2 over the unit cell?
You could do that, but this is already done in Kwant, and you can read the velocities off from the modes object [1].
Best, Anton
[1]: https://kwant-project.org/doc/1/reference/generated/kwant.ph ysics.PropagatingModes#kwant.physics.PropagatingModes
Hi Harshad,
I was able to obtain the velocities from the modes object. I confirmed that modes.velocities is just the inverse of integral |đ|2 over the unit cell. If I did the math correctly, I got the units of modes.velocities to be eV (energy units of my Hamiltonian). How can I convert this to lets say m/s?
Sorry that I forgot to clarify that the unit of length in this case is the side of the lead unit cell. Multiplying by that size should allow to easily translate your velocity into m/s. Anton
participants (2)
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Anton Akhmerov
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Harshad Sahasrabudhe