Mailman 3 October 2016 - lxml - The Python XML Toolkit

an odd result with addprevious
by Martin Mueller 09 Oct '16

09 Oct '16

I am trying to mov e <pb/> elements in a TEI document from a position at the top of a block to a position between the block elements. So I thought up a toy problem, using the following text: <root> <l>Mary had a little lamb, little lamb,</l> <l><pb/>little lamb, Mary had a little lamb</l> <l>whose fleece was white as snow.</l> <l>And everywhere that Mary went</l> <l>Mary went, Mary went, everywhere</l> <l>that Mary went</l> <l> The lamb was sure to go.</l> </root> I used the following code: from lxml import etree Mary = '/users/martin/dropbox/allerlei/Mary.xml' tree = etree.parse(Mary) for pb in tree.iter('pb'): parent = pb.getparent() print(parent.tag) parent.addprevious(pb) print(etree.tostring(tree, encoding='unicode')) This produces the following output: l <root> <l>Mary had a little lamb, little lamb,</l> <pb/>little lamb, Mary had a little lamb<l/> <l>whose fleece was white as snow.</l> <l>And everywhere that Mary went</l> <l>Mary went, Mary went, everywhere</l> <l>that Mary went</l> <l> The lamb was sure to go.</l> </root> The output does most of the things right and moves the pb element from child of l to child of root. But the output doesn’t show the opening tag for the l element, so that the document is not a well-formed document. Oddly enough, this code works as intended in a TEI text were all text is wrapped in <w> elements. Since that is the kind of text I’m working with, I’m happy enough. But I am curious about the dropping of the opening tag of the l element. Is that a bug, am I doing something wrong, or do I just not know enough about “mixed XML”.

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attrname - get value of attrname
by Sayth Renshaw 04 Oct '16

04 Oct '16

Hi I was following this rather old thread https://mailman-mail5.webfaction.com/pipermail/lxml/2011-May/006000.html I noticed in it this excerpt. >* I tend to rather use XPath instead of lxml's ElementPath so you might do s.th <http://s.th>. like: *>>>>>* doc.xpath('//gruppe/@*') *>* ['Einstellung1', 'feld-server', 'feld-bertlap'] *>>>>* for attrResult in doc.xpath('//gruppe/@*'): *>* ... print attrResult.attrname* Ok so applying this to my own xml file I get it to work. In [11]: with open('20160402RAND0.xml', 'r') as f: ...: tree = ET.parse(f) ...: for attrResult in tree.xpath('//meeting/@*'): ...: print(attrResult.attrname) id barriertrial venue date gearchanges stewardsreport gearlist racebook postracestewards meetingtype rail weather trackcondition nomsdeadline weightsdeadline acceptdeadline jockeydeadline Now however I want the values associated with the attributes but how do I get that? For example I cannot seem to iter the result to get the value of the attribute. In [13]: with open('20160402RAND0.xml', 'r') as f: ...: tree = ET.parse(f) ...: for attrResult in tree.xpath('//meeting/@*'): ...: for attrval in attrResult: ...: print(attrResult.get(attrval)) --------------------------------------------------------------------------- AttributeError Traceback (most recent call last) <ipython-input-13-3d77432ea68d> in <module>() 3 for attrResult in tree.xpath('//meeting/@*'): 4 for attrval in attrResult: ----> 5 print(attrResult.get(attrval)) 6 AttributeError: 'lxml.etree._ElementUnicodeResult' object has no attribute 'get' Ideas? Sayth

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transform using XSLT with method="text" has empty result
by Rainer Hoerbe 01 Oct '16

01 Oct '16

I have a style sheet that outputs validation messages as JSON, i.e. output method=„text“. Using xsltproc from libxml2 yields a correct result: xsltproc rules/schtron_xsl/rule00I.xsl testdata/idp_valid.xml "00": { "Severity": "Info", "Message": "Validating entityID https://idp5.test.example.org/idp.xml", "Context“, "/md:EntitiesDescriptor[1]/md:EntityDescriptor[1]", "Rule": "@entityID" } Whereas I get an empty result with lxml: [https://github.com/identinetics/saml_schematron/blob/dev/scripts/try_xslt2t…] import lxml.etree as etree with open('rules/schtron_xsl/rule00I.xsl') as fd: transform = etree.XSLT(etree.XML(''.join(fd.readlines()))) with open('testdata/idp_valid.xml') as fd: md_dom = etree.parse(fd) result_xml = (transform(md_dom)) print(etree.tostring(result_xml)) (Data files relative to https://github.com/identinetics/saml_schematron/blob/dev/) What is the correct method to get non-XML result objects from xslt? Best regards Rainer Hörbe

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