Re: [Python-ideas] Make range objects orderable

On 04/23, Riley Banks wrote:

I propose adding the ability to compare range objects using methods (e.g. range.issubrange) and/or regular operators. Example:

In [56]: range(0, 10, 3).issubrange(range(10))
Out[56]: True

In [57]: range(0, 10, 3) <= range(10)
Out[57]: True

In [58]: range(10) <= range(0, 10, 3)
Out[58]: False

I seem to recall orderable ranges being rejected before. For example, is less-than, or subrange, dependent on the values themselves, or on the lowest and highest values, or on the start and end value, or ...

In other words, given:

a = range(11) b = range(12, step=3)

is a < b, or b < a? Why?

-- ~Ethan~