[BangPypers] Need Help : Setting Floating Precision Point as 2 in Python

[vijay]

Hi Arun,
   Check out this 
>>> a=79.73
>>> b=0.5
>>> c = '%.2f' %(a+b)
>>> c
'80.23'

Hope this help.

With Regards
Vijay


--- On Tue, 24/8/10, Arulalan T <arulalant at gmail.com> wrote:

From: Arulalan T <arulalant at gmail.com>
Subject: [BangPypers] Need Help : Setting Floating Precision Point as 2 in Python
To: "Bangalore Python Users Group - India" <bangpypers at python.org>
Date: Tuesday, 24 August, 2010, 4:05 PM

Dear All,

I need one help.

In python, I need to set the floating point precision as 2.

I am getting the following output in python while adding two float nos.

>>>a=79.73
>>>b=0.5
>>> a+b
80.230000000000004

I need exactly 2 precision point in this float value. i.e. 80.23

Even though I tried in round method, its not satisfied me. Because

>>> a = round(3.7138464897123424324355124355,2)
>>> a
3.71
>>> a = round(3.7238464897123424324355124355,2)
>>> a
3.7200000000000002

Can you understand the difference. Depends upon the value, it will round.

I no need ceil and floor options. Because it may change the original values.

I need just 2 precision point in the float value.

I am getting two numbers dynamically. So I can not say exactly, what kind of
floating numbers I am going to use.

What I have to do ?

Any suggestions ?

Thanks in advance.




-- 
Regards,
Arulalan.T

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