[BangPypers] Need Help : Setting Floating Precision Point as 2 in Python

[Arulalan T]

Hi,

2010/8/24 vijay <vnbang2003 at yahoo.com>

> Hi Arun,
>    Check out this
> >>> a=79.73
> >>> b=0.5
> >>> c = '%.2f' %(a+b)
> >>> c
> '80.23'
>

It is string.
>>> float(c)
80.230000000000004

Again same problem getting . :(
I need it as float only.


>
> Hope this help.
>
> With Regards
> Vijay
>
>
> --- On Tue, 24/8/10, Arulalan T <arulalant at gmail.com> wrote:
>
> From: Arulalan T <arulalant at gmail.com>
> Subject: [BangPypers] Need Help : Setting Floating Precision Point as 2 in
> Python
> To: "Bangalore Python Users Group - India" <bangpypers at python.org>
> Date: Tuesday, 24 August, 2010, 4:05 PM
>
> Dear All,
>
> I need one help.
>
> In python, I need to set the floating point precision as 2.
>
> I am getting the following output in python while adding two float nos.
>
> >>>a=79.73
> >>>b=0.5
> >>> a+b
> 80.230000000000004
>
> I need exactly 2 precision point in this float value. i.e. 80.23
>
> Even though I tried in round method, its not satisfied me. Because
>
> >>> a = round(3.7138464897123424324355124355,2)
> >>> a
> 3.71
> >>> a = round(3.7238464897123424324355124355,2)
> >>> a
> 3.7200000000000002
>
> Can you understand the difference. Depends upon the value, it will round.
>
> I no need ceil and floor options. Because it may change the original
> values.
>
> I need just 2 precision point in the float value.
>
> I am getting two numbers dynamically. So I can not say exactly, what kind
> of
> floating numbers I am going to use.
>
> What I have to do ?
>
> Any suggestions ?
>
> Thanks in advance.
>
>
>
>
> --
> Regards,
> Arulalan.T
>
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-- 
Regards,
Arulalan.T

Kanchi Linux User Group Rocks !
http://kanchilug.wordpress.com

My Experiments In Linux are here
http://tuxcoder.wordpress.com