[C++-sig] Possible overload<> template for class members

[William Trenker]

I've been getting familiar with wrapping overloaded C++ class methods for 
Python using this syntax:

using namespace fltk;
using namespace boost::python;
BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS(show_noArgs, show, 0, 0)
BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS(show_pWindow, show, 1, 1)
BOOST_PYTHON_MODULE(byFLTK)
{
  class_<Window, boost::noncopyable >("Window", init<int,int,const char 
*>())
	.def("show", (void(Window::*)())0, show_noArgs())
	.def("show", (void(Window::*)(const Window*))0, show_pWindow())
	;
}

(Like most GUI's FLTK has many overloaded methods such as window->show() or 
window->show(parent).)

It took me a lot of digging to get BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS() 
and the function casts in the .def's figured out.  But it works just fine.

I don't know b::p well enough yet to submit proposed changes, but I was 
wondering if it would be possible to have a template, possibly called 
"overload", that works for overloded class members like the init<> template 
does for overloaded constructors?  Maybe something like this:

using namespace fltk;
BOOST_PYTHON_MODULE(byFLTK)
{
  class_<Window, boost::noncopyable >("Window", init<int,int,const char 
*>())
	.def("show", overload<void,void>(), &Window::show)
	.def("show", overload<void,const Window*>(), &Window.show)
	;
}

Of course, unlike constructors, a return type has to be provided for member 
functions; so I've just thrown that in as the first parameter in overload<>. 
  Is something like this even possible?

Cheers,
Bill





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