[C++-sig] operator+(A, B) without B::B() default constructor in boost.python

[William Ladwig]

It looks to me like you're missing a '()' next to your 'init<>' in the class wrapper for B.

Try changing this:

  class_<B,boost::noncopyable>("B",init<int>)    //line 19
    ;

to this:

  class_<B,boost::noncopyable>("B",init<int>())    //line 19
    ;

The only operator that has given me problems is the << operator.  I've had pretty good success with the others.

Regards,
Bill

-----Original Message-----
From: cplusplus-sig-bounces+wladwig=wdtinc.com at python.org [mailto:cplusplus-sig-bounces+wladwig=wdtinc.com at python.org] On Behalf Of Hans Roessler
Sent: Thursday, May 14, 2009 8:16 AM
To: cplusplus-sig at python.org
Subject: [C++-sig] operator+(A, B) without B::B() default constructor in boost.python


Hello,
how can I wrap the following overloaded operator+ using boost.python?
The code as is fails with 
>...
>pytest.cpp: In function 'void init_module_pytest()':
>pytest.cpp:19: error: expected primary-expression before '(' token
>...
If I try ".def(self+B())" instead of ".def(self+other<B>())", the error is
>...
>pytest.cpp: In function 'void init_module_pytest()':
>pytest.cpp:17: error: no matching function for call to 'B::B()'
>...

best wishes
Hans


pytest.cpp:

#include <boost/python.hpp>
using namespace boost::python;

class A{
public:
};
class B{
public:
  B(int i){};
};

int operator+(const A& a,const B& b){return 42;};

BOOST_PYTHON_MODULE(pytest)
{
  class_<A>("A")
    .def(self+other<B>())   //.def(self+B())            //line 17
    ;
  class_<B,boost::noncopyable>("B",init<int>)    //line 19
    ;
}


      
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