[Mailman-Users] regexp help

[Mark Sapiro]

Savoy, Jim wrote:

>>Mark Sapiro wrote:
>
>>What you need is a custom handler. See the FAQ at
><http://wiki.list.org/x/l4A9> for how to install one.
>
>Thank you. Done.
>
>>In your case, the handler is very simple - just 9 lines.
>
>>import re
>>cre = re.compile('unique\.name', re.IGNORECASE)
>>def process(mlist, msg, msgdata):
>>    if mlist.internal_name <> 'abc-l':
>>        return
>>    if cre.search(msg.get('to', '')):
>>        msgdata['approved'] = 1
>>        # Used by the Emergency module
>>        msgdata['adminapproved'] = 1
>
>>Of course, you adjust the regexp 'unique\.name' and the list name
>>'abc-l' to suit. The handler needs to be in the pipeline before
>>Moderate.
>
>OK - I made a file called Foo.py and put it in /Mailman/Handlers.
>I then inserted this module right before 'Moderate' in the pipeline (I
>editted
>Defaults.py for this - just as a temporary measure to see if it would
>work).
>I will remove this and add a line to mm_cfg.py later.
>
>I then stopped/started the Mailman processes (not sure if that's
>necessary, but 
>I did it anyway). Now the test email I sent is stuck in the shunt queue
>and this
>is in the errors log:
>
>File "/Mailman/Handlers/Foo.py", line 2
>     cre = re.compile('unique\.name', re.IGNORECASE) def process(mlist,
>msg, msgdata):
>                                                       ^
> SyntaxError: invalid syntax


You used some kind of word processor to create foo.py that concatenated
lines 2 and 3 into a single line. Your Foo.py file must be just like
my original example with lines 1, 2 and 3 at the left margin, lines 4
and 6 indented 4 spaces and lines 5, 7, 8 and 9 indented 8 spaces.

-- 
Mark Sapiro <mark at msapiro.net>        The highway is for gamblers,
San Francisco Bay Area, California    better use your sense - B. Dylan