[ python-Bugs-1280061 ] time.strptime() fails with unicode date string, de_DE locale

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Bugs item #1280061, was opened at 2005-09-01 13:06
Message generated for change (Comment added) made by bcannon
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Category: Python Library
Group: Python 2.4
Status: Open
Resolution: None
Priority: 5
Submitted By: Adam Monsen (meonkeys)
>Assigned to: Brett Cannon (bcannon)
Summary: time.strptime() fails with unicode date string, de_DE locale

Initial Comment:
Trying to parse a German date string fails in Python
2.4.1. Test case attached.

Since there's no indenting, I suppose the test case can
also be pasted here:

import locale, time
locale.setlocale(locale.LC_TIME, 'de_DE')
date = u'10. September 2005 um 17:26'
format = '%d. %B %Y um %H:%M'
time.strptime(date, format)

--
Adam Monsen
http://adammonsen.com/

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>Comment By: Brett Cannon (bcannon)
Date: 2005-09-02 13:37

Message:
Logged In: YES 
user_id=357491

Can you let me know what time.strftime() outputs for your
test case, specifically what type of basestring (str or
unicode)?

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Comment By: Adam Monsen (meonkeys)
Date: 2005-09-02 09:43

Message:
Logged In: YES 
user_id=259388

Here's a simpler, more precise test case (also attached):

import locale, time
locale.setlocale(locale.LC_TIME, 'de_DE')
date = u'September'; format = '%B'
time.strptime(date, format)

Here's the error I see:

Traceback (most recent call last):
  File "de_strptime_fail_simple.py", line 4, in ?
    time.strptime(date, format)
  File "/usr/lib/python2.4/_strptime.py", line 329, in strptime
    month = locale_time.f_month.index(found_dict['B'].lower())
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe4 in
position 1: ordinal not in range(128)

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