[Python-Dev] closure semantics
Delaney, Timothy C (Timothy)
tdelaney at avaya.com
Fri Oct 24 02:25:52 EDT 2003
> From: Greg Ewing [mailto:greg at cosc.canterbury.ac.nz]
> > It would break any unadorned 'global x' in a nested scope
> if the name
> > did not exist anywhere.
> > One option would be to have an "if the name doesn't exist, it it
> > created in module scope".
> What would be wrong with that? It's what I had in mind.
It's complex. Can you explain the complete semantics of 'outer' as simply as:
global <name> [in <scope>]
Binds and uses <name> in another scope. If 'in <scope>' is omitted
then the name is bound and used in the scope of the current module.
My understanding of 'outer' is (and I'm not sure about this):
Binds and uses <name> in the innermost scope containing the current
scope that already has <name> bound. If <name> is not bound in any
containing scope then it is bound into the scope of the current
module if <name> is used or bound while executing in the current
<include warnings about introducing the name into a scope between the
current scope and the scope where the programmer was expecting the
name to be bound>
Or something like that.
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