[Python-ideas] Adding exception logging function to syslog module.

[Eric Smith]

Eric Smith wrote:
> I think this would be a great addition. I have to do similar things all 
> of the time, although I never though of using sys.excepthook, for some 
> reason. I'll have to steal your code in the meantime!
> 
> A simpler pure Python version would be:
> 
> from __future__ import print_function
> 
> def logexceptions(also_stderr=True):
>     import sys
>     import traceback
>     import syslog
>     def syslog_exception(etype, evalue, etb):
>         # The result of traceback.format_exception might contain
> 
>         # embedded newlines, so we have the nested loops.
> 
>         for line in traceback.format_exception(etype, evalue, etb):
>             for line in line.rstrip().split('\n'):
>                 syslog.syslog(line)
>                 if also_stderr:
>                     print(line, file=sys.stderr)
>     sys.excepthook = syslog_exception
> 
> logexceptions(True)

On second thought, maybe it would be better to optionally chain to the 
existing sys.excepthook instead of assuming it writes to stderr. The 
above code would become:

def logexceptions(chain=True):
     import sys
     import traceback
     import syslog
     current_hook = sys.excepthook
     def syslog_exception(etype, evalue, etb):
         if chain:
             current_hook(etype, evalue, etb)
         # The result of traceback.format_exception might contain 
 

         # embedded newlines, so we have the nested loops. 
 

         for line in traceback.format_exception(etype, evalue, etb):
             for line in line.rstrip().split('\n'):
                 syslog.syslog(line)
     sys.excepthook = syslog_exception

I think I'll open an issue for this. I don't think the language 
moratorium would preclude its addition.

Eric.


-- 
Eric.