opening more than 1 file

[Skip Montanaro]

martin van nijnatten wrote:
> 
> I have a variable, which can have a value in the range from 1 to 20.
> 
> If the value is 7, I have to open 7 files.
> 
> What could be an elegant way of doing this?

Well, how about:

    files = []
    for i in range(nfiles):
        files.append(open("/tmp/file%03d"%i, "wb"))

then access the i-th file as files[i]?

-- 
Skip Montanaro	| Mojam: "Uniting the World of Music"
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