regex's

[chibaA at TinterlogD.Tcom]

Perfect!

Thanks muchly!

kc


On Wed, 05 Jul 2000 01:47:49 GMT, Tim Hochberg <tim.hochberg at ieee.org>
wrote:

>chibaA at TinterlogD.Tcom writes:
>
>> Hi...  I'm having a bit of a brain-tease...  I have the following code
>> (example):
>> 
>> import re
>> 
>> str = '123'
>> if re.compile('1').match(str):
>> 	print "matched 1"
>> if re.compile('2').match(str):
>> 	print "matched 2"
>> if re.compile('3').match(str):
>> 	print "matched 3"
>> 
>> -------------------
>> 
>> I would think that this code would print 'matched 1 matched 2 matched
>> 3'...  But in this case, it would only printed "matched 1".  Any
>> reasons?  Is there any way to have it print all three (since the
>> conditions seem to be true)?
>
>re.match matches from the beginning of the string (e.g.,
>re.compile('2').match(str) will only match strings starting with
>'2'. What you want is re.search. For example:
>
>#....
>if re.compile('2').search(str):
>	# ...
>
>You could also use:
>
>#....
>if re.search('2', str):
>	# ...
>
>However, the former will be faster if you reuse the regular
>expression since you can compile it once and reuse the compiled
>version.
>
>
>-tim
> 
>> Thanks in advance!
>> 
>> kc.
>