float does not parse '0.000000E+00'
Darrell Gallion
darrell at dorb.com
Sun Jun 4 00:33:36 EDT 2000
Too much work to decode what your doing.
Maybe this will help.
import pprint, string
def parse(lines):
res=[]
for l in lines:
temp = string.split(l)
resLine=[]
for n in temp:
resLine.append(eval(n))
res.append(resLine)
return res
pprint.pprint(parse(open("lcase.001").readlines()))
############ Output
[[1],
[4, 3],
[1, 0.0, 0.0],
[2, 0.0, 300.0],
[3, 500.0, 300.0],
[4, 500.0, 0.0],
[1, 1, 2],
[2, 2, 3],
[3, 3, 4],
[1, 300.0, 0.0, 1.0],
[0.0, 0.0, 0.0, 2500.0, -146.922, 6526.54],
.....
--Darrell Gallion
Paolo Redaelli wrote:
>
> but if I run a program that does x=float(x) where x = "0.000000E+00 "
> (being a string) here's the output.
>
> ===========================
> [paolo at aldebaran Telaio]$ ./pyplot.py
> x(<type 'string'>)='0.000000E+00' y(<type 'string'>)='0.000000E+00'
> Traceback (innermost last):
> File "./pyplot.py", line 198, in ?
> t = Telaio()
> File "./pyplot.py", line 172, in __init__
> x = float(x)
> ===========================
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