Solution for python22_d.lib

[Martin v. Loewis]

seb_haase at yahoo.com (Sebastian Haase) writes:

> I think that wouldn't work - since I'm still interested in debugging
> _my_ stuff - so that needs me to #define _DEBUG

Can you elaborate? If you want code that is only active under
debugging, why can't you wrap it in #ifdef HAASE_DEBUG or some such?

If you think that you would not get symbolic debugger support if
_DEBUG is not defined, you are wrong.

Regards,
Martin