v # invalid expression ?
Anthony Liu
antonyliu2002 at yahoo.com
Thu Mar 11 04:16:03 EST 2004
I am trying to split a string like so:
re.split(',|。|、|!|:|,|?|||)|(|;',
my_string)
Python complains like so:
Traceback (most recent call last):
File "C:\Python23\codes\regextest.py", line 27, in
-toplevel-
ultimate =
re.split(',|。|、|!|:|,|?|||)|(|;',
ch[0])
File "c:\python23\lib\sre.py", line 156, in split
return _compile(pattern, 0).split(string,
maxsplit)
File "c:\python23\lib\sre.py", line 229, in _compile
raise error, v # invalid expression
error: nothing to repeat
Does this mean that the regular expression I pass to
the split function is not valid?
That expression is just like ',|)|#|!', that is, an
or-ed list of punctuations. Then why invalid?
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