problem of converting a list to dict

[Reedick, Andrew]

> -----Original Message-----
> From: python-list-bounces+jr9445=att.com at python.org [mailto:python-
> list-bounces+jr9445=att.com at python.org] On Behalf Of John Machin
> Sent: Wednesday, January 09, 2008 3:02 PM
> To: python-list at python.org
> Subject: Re: problem of converting a list to dict
> 
> On Jan 10, 6:52 am, "Reedick, Andrew" <jr9... at ATT.COM> wrote:
> >
> > A bigger hint:
> >         a=i.split('=')
> >         print "'%s' splits into " % (i), a
> 
> consider:
> (1) using %r instead of '%s'

	Eh, personal preference depending on how sure you are of the
data's type. 

> (2) omitting the redundant space after 'into'

	Some of us coming in from other languages and still aren't used
to the comma adding an unwanted space after everything.  I've been
tempted to root around in Python's source code to fix the problem.

> (3) losing the redundant () around i

	For me, the () is there for readability.  Python's sprintf
syntax is odd to begin with, and something like 
		print "'%s' splits into " % i, a, b, c
	means either
		1) you really do want to append b and c after the
sprintf, or
			print "'%s' splits into " % (a), b, c
		2) that the formatting string is missing a few things 
			print "'%s' splits into " % (a, b, c)  ## Ooops!
forgot to change it to "%s %5.2d %6.3f"
	

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