COM server and EXE

[Giles Brown]

On 8 Jan, 11:04, Teja <tejovath... at gmail.com> wrote:
> On Jan 8, 3:33 pm, Teja <tejovath... at gmail.com> wrote:
>
>
>
> > Hi All,
>
> > I have a Python COM server. I need to deploy it on various sytems.
> > When I run the COM server from
> > python its showing an output " Registered : sample.lib"
>
> > If I try to use the COM obj from a VB client like:
>
> > obj = CreateObject("sample.lib")
>
> > Its working fine without any errors
>
> > Now I am trying to convert this COM server to an exe through py2exe
> > and after I run the exe, I am
> > getting the same output " Registered : sample.lib"
>
> > But If I try to use the COM obj from a VB client like
>
> > obj = CreateObject("sample.lib")
>
> > A console pops up saying " Registered : sample.lib" and VB application
> > hangs there.
> > Its throwing a VB error that "ActiveX object cannot be
> > created......etc etc"
>
> > Any suggestions please.......
>
> > Regards,
> > Tejovathi
>
> Here is my sample COM server and py2exe setup file
>
> testCOM.py
>
> import win32com.client
> import os.path
> import shutil
> from win32api import Sleep
> import string
> import os
> import sys
> import pythoncom
>
> class FirstEx:
>
>     _reg_clsid_ = "{A6DE9DF8-5EBF-48E6-889E-C71CB84CFF2C}"
>     pythoncom.frozen = 1
>     if hasattr(sys, 'importers'):
>         # In the py2exe-packed version, specify the module.class
>         # to use. In the python script version, python is able
>         # to figure it out itself.
>         _reg_class_spec_ = "__main__.FirstEx"
>     _reg_desc_ = "My first COM server"
>     _reg_progid_ = "SAMPLE.Lib"
>     _public_methods_ = ['init', 'Version']
>     _public_attrs_ = ['softspace', 'noCalls']
>     _readonly_attrs_ = ['noCalls']
>     _reg_clsctx_ = pythoncom.CLSCTX_LOCAL_SERVER
>
>     def __init__(self):
>         self.softspace = 1
>         self.noCalls = 0
>
>     def Version(self):
>         self.noCalls = self.noCalls + 1
>
>         # insert "softspace" number of spaces
>         return "Version: 0.0.1"
>
> if __name__=='__main__':
>     import sys
>     if hasattr(sys, 'importers'):
>         # running as packed executable.
>         if '--register' in sys.argv[1:] or '--unregister' in
> sys.argv[1:]:
>         # --register and --unregister work as usual
>             import win32com.server.register
>             win32com.server.register.UseCommandLine(FirstEx)
>         else:
>             # start the server.
>             from win32com.server import localserver
>             localserver.main()
>     else:
>         import win32com.server.register
>         win32com.server.register.UseCommandLine(FirstEx)
>
>  Here is my setup file:
>
> #Start here
> from distutils.core import setup
> import py2exe
>
> setup(options = {"py2exe": {"compressed": 1,
>                           "optimize": 2,
>                           "ascii": 1,
>                           "bundle_files": 1}},
>     zipfile = None,
>     com_server = ["win32com.servers.interp"],
>     console = ["testCOM.py"])
> #End here
>
> Here is my VB code:
>
> Sub subRoutine()
> Dim connection As Object
> Dim returnvalue1 As String
> Dim returnvalue2 As String
> Dim flag3 As Boolean
>
> Set connection = CreateObject("SAMPLE.Lib")
> returnvalue1 = connection.Version()
> MsgBox (returnvalue1)
> End Sub
>
> The non exe version of the COM server ie. directlly running the
> testCOM.py registers the library properly and
>
> in the VB application, the message box displays the version as 0.0.1.
>
> But, after I create the EXE file using the setup.py file and run it,
> it registers the library.
>
> When I run the VB application, it hangs at the line
>
> Set connection = CreateObject("SAMPLE.Lib")
>
> and displays. " ACTIVEX cannot create the object"
>
> Any suggestions please....

A quick suggestion (didn't read very carefully sorry).
Make sure you register it with --debug and use the pythonwin tools-
>trace collector debugging tool.
See if you get any joy.  It may be you missed some vital library in
your py2exe
that causes a start-up time failure.

Giles