choosing random dynamic port number

[Grant Edwards]

On 2008-01-04, Giampaolo Rodola' <gnewsg at gmail.com> wrote:

>>     def GenerateDynamicPortNumber():
>>         return 0
>>
>> (to get the actual number, use getsockname() on the socket after you've
>> called "bind" on it)
>>
>> </F>
>
> By using 0 as port number value you let kernel choose a free
> unprivileged random port:

The port number chosen isn't random on many OSes.  If the OP
really wants a random port number, he'll have to generate it
himself.

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