do you fail at FizzBuzz? simple prog test

[John Machin]

Duncan Booth wrote:
> Ivan Illarionov <ivan.illarionov at gmail.com> wrote:
> 
>>>> is there a better way than my solution? is mine ok?
>>> ['%s%s' % (not i%3 and 'Fizz' or '', not i%5 and 'Buzz' or '')
>>>  or str(i) for i in xrange(1, 101)]
>>>
>>> -- Ivan
>> or, more correctly, if you actually need to "print":
>>
>> sys.stdout.write('\n'.join('%s%s' % 
>>     (not i%3 and 'Fizz' or '', not i%5 aBuzz' or '') 
>>     or str(i) 
>>     for i in xrange(1, 101)))
> 
> I think the variant I came up with is a bit clearer:
> 
> for i in range(1,101):
> 	print '%s%s' % ('' if i%3 else 'Fizz', '' if i%5 else 'Buzz') or i

More than a bit clearer, IMO. How about
     print ('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz') or i
(or perhaps
     print (('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz')) or i
to save looking up the precedence rules) ?