do you fail at FizzBuzz? simple prog test

[Arnaud Delobelle]

On May 12, 1:30 pm, John Machin <sjmac... at lexicon.net> wrote:
> Duncan Booth wrote:
[...]
> > I think the variant I came up with is a bit clearer:
>
> > for i in range(1,101):
> >    print '%s%s' % ('' if i%3 else 'Fizz', '' if i%5 else 'Buzz') or i
>
> More than a bit clearer, IMO. How about
>      print ('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz') or i
> (or perhaps
>      print (('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz')) or i
> to save looking up the precedence rules) ?

Stuff clarity!  How about

for i in xrange(1, 101):
    print 'FizzBuzz'[4*(i%3>0):4+4*(i%5<1)] or i

--
Arnaud