checking 'type' programmatically

mk mrkafk at gmail.com
Fri Nov 20 11:10:18 CET 2009


Disclaimer: this is for exploring and debugging only. Really.

I can check type or __class__ in the interactive interpreter:

Python 2.6.2 (r262:71600, Jun 16 2009, 16:49:04)
[GCC 4.1.2 20080704 (Red Hat 4.1.2-44)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
 >>> import subprocess
 >>> 
p=subprocess.Popen(['/bin/ls'],stdout=subprocess.PIPE,stderr=subprocess.PIPE)
 >>> p
<subprocess.Popen object at 0xb7f2010c>
 >>> (so, se) = p.communicate()
 >>> so
'abc.txt\nbak\nbox\nbuild\ndead.letter\nDesktop\nhrs\nmbox\nmmultbench\nmmultbench.c\npyinstaller\nscreenlog.0\nshutdown\ntaddm_import.log\nv2\nvm\nworkspace\n'
 >>> se
''
 >>> so.__class__
<type 'str'>
 >>> type(so)
<type 'str'>
 >>> type(se)
<type 'str'>

But when I do smth like this in code that is ran non-interactively (as 
normal program):

req.write('stderr type %s<br>' % type(se))
req.write('stderr class %s<br>' % str(se.__class__))

then I get empty output. WTF?

How do I get the type or __class__ into some object that I can display?


Why do that: e.g. if documentation is incomplete, e.g. documentation on 
Popen.communicate() says "communicate() returns a tuple (stdoutdata, 
stderrdata)" but doesn't say what is the class of stdoutdata and 
stderrdata (a file object to read? a string?).

Regards,
mk






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