super in Python 3 and variadic arguments

[Steven D'Aprano]

On Thu, 10 Oct 2013 07:04:38 -0400, Ned Batchelder wrote:

> super() with no args is a kind of hack to begin with.  It involves a
> special case in the compiler (so that using the name "super" as a
> function call will act as if you had accessed the name "__class__" so
> that super can find it later), and inspecting the stack frame during
> execution.

super() with no arguments is *completely* a hack[1], and one where GvR 
has said "Never again!" if I remember correctly. I don't think he regrets 
allowing the super compile-time magic, just that it really is magic and 
he doesn't want to make a habit of it.

One of the side-effects of this being a hack is that this doesn't work:

class X(Y):
    def method(self, arg):
        f = super
        f().method(arg)





[1] Which is not necessarily a bad thing!

-- 
Steven