[python-win32] Bug - Passing byref an array to a com method interpreted as a single element

[rvc69]

Hello TimThank you for your response and time.Best regardsHerve 


Envoyé depuis mon smartphone Samsung Galaxy.
-------- Message d'origine --------De : Tim Roberts <timr at probo.com> Date : 21/01/2019  18:57  (GMT+01:00) À : Python-Win32 List <python-win32 at python.org> Objet : Re: [python-win32] Bug - Passing byref an array to a com method interpreted as a single element 
rvc69 at free.fr wrote:
>
> I'm trying to translate a VBA application to Python. I cannot change 
> the COM Server as its works also with others programs.
> It seems I have a problem with win32com.client by passing an array of 
> double to a COM method.
>
> VBA allows to pass arrays to COM server byref on the first element of 
> the array
> ...||
>
> From typelib COM interface
>
> |[id(0x00000007), helpstring("Méthode GetValues")] HRESULT 
> GetValues([in, out] double* pValues); # pointer on array of double 
> [id(0x00000008), helpstring("Méthode SetValues")] HRESULT 
> SetValues([in] double* pValues);|

...

> It seems win32client do not interpret correctly the type expected by 
> the COM server, here float() instead of pointer on an array of float.
>

That statement is not accurate.  The fault is not in win32client.  The 
root of the problem is that the function definition in your type library 
is not COM-compliant.  There are rules that need to be followed in order 
for a COM interface to work seamlessly across languages, and you have 
violated those rules.  The proper way to pass an array is to use a 
SAFEARRAY. Your definition, for example, cannot possibly work in an 
out-of-process server, because there is no way for the marashaling code 
to know how much data to send across.  The GetValues case is doubly 
hopeless.  How can the server know how large the buffer is?  How can the 
client know how much data will be returned?  You are simply not allowed 
in COM to have that be assumed.


Win32client is quite correct in interpreting your definition as it 
does.  The fact that it works in VBA is an lucky accident.  If you want 
this to work reliably, you need to change the interface.

-- 
Tim Roberts, timr at probo.com
Providenza & Boekelheide, Inc.

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