[SciPy-user] Matlab to numpy

[Nils Wagner]

David Douard wrote:
> On Thu, Jun 22, 2006 at 01:59:45PM +0200, Nils Wagner wrote:
>   
>>  I try to convert a Matlab code into Numpy/Scipy
>>
>> What is equaivalent to
>>
>> np = 36
>> t2 =rand(np,1)
>> r2=rand(np,1)./max(abs(sin(t2)),abs(cos(t2)))
>>
>> in numpy
>>
>> np=36
>> t2 = rand(np)
>> r2 = rand(np)/...  ?
>>     
>
> I would say, using numpy
>
> from numpy import *
> np = 36
> t2 = rand(np)
> r2 = rand(np)/maximum(absolute(sin(t2)),absolute(cos(t2)))
>
>
> David
>
>   
>> Nils
>>
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>>     
>
>   
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>   
Thank you very much.
And what is equivalent to a so-called economy size decomposition ?

[Q,R] = qr(A,0)


Nils