[Tutor] getting the current method name

[Magnus Lyckå]

At Thu, 17 Apr 2003 09:11:02 +0200, Adam Groszer wrote:
>how to do the following:
>
>class x:
>         def y():
>                 print "Hi, my name is",<<method-name --> 'y'>>
>
>z=x()
>z.y()
>should print
>"Hi, my name is y"
>
>Of course, resolving "<<method-name --> 'y'>>" should not be done with
>simply 'y' :-)

Did that! See

http://cvs.sourceforge.net/cgi-bin/viewcvs.cgi/systemspecifyer/src/matrix.py?rev=1.16&content-type=text/vnd.viewcvs-markup

Python is certainly capable of introspection.
This function does the trick!:

 >>> import sys
 >>> def _fn():
...     return sys._getframe(1).f_code.co_name
...
 >>> class X:
...     def y(self):
...             print _fn()
...
 >>> x = X()
 >>> x.y()
y

Another option is to write:

 >>> class X:
...     def y(self):
...             print sys._getframe(0).f_code.co_name
...
 >>> x = X()
 >>> x.y()
y

Notice 0 instead of one. Now we want the top-most (or
is it bottom-most) frame.

I prefer a separate (well commented?) function for
such magic though...

The docs say about sys._getframe that "This function
should be used for internal and specialized purposes only."

What does this really imply? That we can't expect the API
to remain?