[Tutor] In-place expansion of list members... possible?
Eric Brunson
brunson at brunson.com
Wed Nov 7 22:38:29 CET 2007
Kent Johnson wrote:
> Marc Tompkins wrote:
>
>> I'm working with delimited files (ANSI X12 EDI nonsense, to be
>> precise.) First I load the records to a list:
>> tmpSegs = inString.split(self.SegTerm)
>>
>> Now, I want to replace each string in that list with a string:
>>
>> for seg in tmpSegs: # 'seg' is short for 'segment'
>> seg = seg.split(self.ElemSep)
>>
>> It doesn't work. If I check the contents of tmpSegs, it's still a list
>> of strings - not a list of lists. So I do this instead:
>> tmpSegs2 = []
>> for seg in tmpSegs:
>> tmpSegs2.append(seg.split(self.sElemSep))
>> del tmpSegs
>>
>> This works. And, for the size of files that I'm likely to run into,
>> creating the extra list and burning the old one is probably not going to
>> swamp the machine - but it feels clumsy to me, like if I just knew the
>> secret I could be much more elegant about it.
>>
>
> Creating a new list is fine, actually. You can do it more elegantly with
> a list comprehension, and it's fine to assign to the same name, which
> will implicitly delete the old list:
> tmpSegs = [ seg.split(self.ElemSep) for seg in tmpSegs ]
>
> If you really want to replace elements in the same list you can use
> enumerate to get indices:
>
> for i, seg in enumerate(tmpSegs):
> tmpSegs[i] = seg.split(self.ElemSep)
>
Very nice use of enumerate(), I like this better than my solution.
Thanks, Kent.
> or use slice assignment:
> tmpSegs[:] = [ seg.split(self.ElemSep) for seg in tmpSegs ]
>
> but I doubt those are needed in this case.
>
>
>> What puzzles me most is that I can replace 'seg' with just about
>> anything else -
>> for seg in tmpSegs:
>> seg = seg.strip()
>> or
>> for seg in tmpSegs:
>> seg = 'bananas'
>> or
>> for seg in tmpSegs:
>> seg = seg + ' bananas'
>> and it works. So why can't I replace it with its own split?
>>
>
> If by 'it works' you mean that tmpSegs is changed...you are mistaken or
> there is something you are not showing. Can you show why you think this
> changes tmpSegs?
>
> Kent
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