[Tutor] Confusion about definition of proper subset in python set
Alan Gauld
alan.gauld at yahoo.co.uk
Fri Oct 30 05:00:02 EDT 2020
On 30/10/2020 02:52, Manprit Singh wrote:
> Test whether the set is a proper subset of *other*, that is, set <= other
> and set != other.
>
> This confuses me actually.
>
> set <= other and set != other , how it is possible at same time ?
Very easily.
S = {1,2,3}
ss = {1}
Now ss is a subset of S.
But ss is not equal to S.
Therefore ss is a proper subset of S.
What is confusing you?
> As far as i know, if S is a set and ss is its proper subset, then ss is
> strictly contained in S and necessarily excludes at least one member of S.
That is correct and exactly what the documentation says.
--
Alan G
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