Also, there is a "non-method" way: the .T property:
a = np. matrix([[1,2,3],[4,5,6],[7,8,9]]) a matrix([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) b = a.T b matrix([[1, 4, 7], [2, 5, 8], [3, 6, 9]])
DG --- On Mon, 7/6/09, Chris Colbert <sccolbert@gmail.com> wrote:
From: Chris Colbert <sccolbert@gmail.com> Subject: Re: [Numpy-discussion] transpose of a matrix should be another matrix To: "Discussion of Numerical Python" <numpy-discussion@scipy.org> Date: Monday, July 6, 2009, 10:42 PM you actually have to call the method as transpose(). What you requested was the actual method.
import numpy as np a = np. matrix([[1,2,3],[4,5,6],[7,8,9]]) a matrix([[1, 2, 3],
[4, 5, 6], [7, 8, 9]])
b = a.transpose() b matrix([[1, 4, 7], [2, 5, 8], [3, 6, 9]])
On Tue, Jul 7, 2009 at 1:34 AM, Dr. Phillip M. Feldman <pfeldman@verizon.net> wrote:
I'm using the Enthought Python Distribution. When I define a matrix and
transpose it, it appears that the result is no longer a matrix (see below).
This is both surprising and disappointing. Any suggestions will be
appreciated.
In [16]: A=matrix([[1,2,3],[4,5,6],[7,8,9]])
In [17]: B=A.transpose
In [18]: A
Out[18]:
matrix([[1, 2, 3],
[4, 5, 6],
[7, 8, 9]])
In [19]: B
Out[19]: <built-in method transpose of matrix object at 0x00CF2A30>
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