[Python-Dev] zipfile.py
M.-A. Lemburg
mal@lemburg.com
Sat, 18 Dec 1999 14:17:52 +0100
"James C. Ahlstrom" wrote:
>
> "M.-A. Lemburg" wrote:
> >
> > "James C. Ahlstrom" wrote:
> > > > ftp://ftp.interet.com/pub/pylib.html
> > >
>
> > Unfortunately, I always get the following traceback when trying
> > to print the directory:
>
> Yes, compression isn't there yet. I am looking into it.
Great :-)
> > Some notes on the API:
> > ----------------------
> > * I would find it more convenient if the filename and mode
> > would be constructor parameters, e.g.
> >
> > zfile = zipfile('myfile.zip','rb')
>
> OK, done.
>
> > with compression defaulting to 8 rather than 0 (most zip files
> > will be deflated since this is the ZIP default).
>
> Until compression works, and zlib ships with Python I
> would rather default to no compression (method 0). Otherwise
> this is not useful as a Python import archive.
Point taken.
Perhaps it would be even better to not have a
default at all: that way people will have to think about the
issue *before* implementing it, rather than debug code
that produces tracebacks.
> > * Also, I would like a method much like the os.listdir()
> > which returns a list of filenames rather than print it
> > to stdout.
>
> OK, done.
>
> > * .is_zipfile() should probably be a separate function: it
> > doesn't use any of the class' features.
>
> OK, done.
Thanks,
--
Marc-Andre Lemburg
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