Hello!
Suppose I'm on 64-bit machine and there is an `a = arrar.array('L',
[0])` (item size is 8 bytes). In Python, when an integer does not fit
machine width it gets promoted to "long" integer of arbitrary size. So
this will fail:
a[0] = 2**63 << 1
To fix this, one could instead write:
a[0] = (2**63 << 1) & (2**64 - 1)
My question is, when I know that the result will be stored in
`array.array` anyway, how to prevent the promotion to long integers?
What is the most …
[View More]performat way to perform such calculations? Is PyPy
able to optimize away that `& (2**64 - 1)` when I use `'L'` typecode?
I mean, in C I wouldn't have to worry about it as everything above the
63rd bit will be simply cut off. I would like to help PyPy to generate
the best possible code, does anyone have some suggestions please?
Thanks!
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